(x)=8x^2+3x-96

Solution for (x)=8x^2+3x-96 equation:

(x)=8x^2+3x-96

We move all terms to the left:

(x)-(8x^2+3x-96)=0

We get rid of parentheses

-8x^2+x-3x+96=0

We add all the numbers together, and all the variables

-8x^2-2x+96=0

a = -8; b = -2; c = +96;
Δ = b2-4ac
Δ = -22-4·(-8)·96
Δ = 3076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3076}=\sqrt{4*769}=\sqrt{4}*\sqrt{769}=2\sqrt{769}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{769}}{2*-8}=\frac{2-2\sqrt{769}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{769}}{2*-8}=\frac{2+2\sqrt{769}}{-16}
$